Q. 34

# Factorise:</p

(i) Given that: 1 + 64x3

= 1 + (4x)3

= (1 + 4x)[(1)2 − (1)(4x) + (4x)2]

[ a3 + b3 = (a + b)(a2 – ab + b2) ]

= (1 + 4x)(1 – 4x + 16x2)

(ii) Given that: a3 − 2√2b3

= (a)3 − (√2b)3

= (a − √2b) [(a)2 + (a)(√2b) + (√2b)2]

[ a3 – b3 = (a + b)(a2 + ab + b2) ]

= (a − √2b)(a2 + √2ab + 2b2)

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