Q. 285.0( 1 Vote )

# Expand the follow

Given that: (4a β b + 2c) 2

= (4a) 2 + (βb) 2 + (2c)2 + 2(4a)(βb) + 2(βb)(2c) + 2(2c)(4a)

[β΅ (a + b + c) 2 = a2 + b2 + c2 + 2ab + 2bc + 2ca)]

= 16a2 + b2 + 4c2 β 8ab β 4bc + 16ca

(ii). Given that: (3π β 5π β π)2

= (3a)2 + (β5b)2 + (βc)2 + 2(3a)(β5b) + 2(β5b)(βc) + 2(βc)(3a)

[β΅ (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca)]

= 9a2 + 25b2 + c2 β 30ab + 10bc β 6ca

(iii). Given that: (βπ₯ + 2π¦ β 3π§)2

= (βπ₯)2 + (2π¦)2 + (β3π§)2 + 2(βπ₯)(2π¦) + 2(2π¦)(β3π§) + 2(β3π§)(βπ₯)

[β΅ (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca)]

= x2 + y2 + 9z2 β 4xy β 12yz + 6zx

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