Q. 24 C5.0( 1 Vote )

Factorise:
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Answer :

π‘₯3 + π‘₯2 – 4π‘₯ – 4


Let p(x) = π‘₯3 + π‘₯2 – 4π‘₯ – 4


p (1) = 1 + 1 – 4 – 4 β‰  0


β‡’ (x – 1) is not a factor of p(x)


p ( – 1) = ( – 1)3 + ( – 1)2 – 4( – 1) – 4


β‡’ – 1 + 1 + 4 – 4 = 0


β‡’ x + 1 is the factor of p(x)



p(x) = (x + 1)( x – 2) (x + 2)


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