Answer :
π₯3 + π₯2 β 4π₯ β 4
Let p(x) = π₯3 + π₯2 β 4π₯ β 4
p (1) = 1 + 1 β 4 β 4 β 0
β (x β 1) is not a factor of p(x)
p ( β 1) = ( β 1)3 + ( β 1)2 β 4( β 1) β 4
β β 1 + 1 + 4 β 4 = 0
β x + 1 is the factor of p(x)
p(x) = (x + 1)( x β 2) (x + 2)
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