Q. 23 B4.4( 17 Votes )

# Factorise:6x2 + 7x – 3

6x2 + 7x – 3

The product of 1st and the 3rd term i.e. 18 can be factorized such that the sum or difference should be equal to the middle term.

Thus, the factors of 18 are 2 and 7

6x2 + 7x – 3

6x2 + 9x – 2x – 3

3x(2+3) – 1(2x+3)

(3x – 1) (2x+3) Ans.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Polynomials - Zero to Hero42 mins  Genius Quiz | Polynomials40 mins  Zeros and Degrees of a Polynomial41 mins  Genius Quiz | Division of Algebraic Expressions37 mins  Introduction to Polynomials37 mins  Quiz | Imp. Qs. on Algebraic Identities65 mins  Basic understanding of Polynomials37 mins  Champ Quiz | Polynomials29 mins  QUiz on Previous year NTSE Questions45 mins  Methods to find zeroes of a polynomial 139 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

Factorize:

x3 – 2x2y + 3xy2 – 6y3

RS Aggarwal & V Aggarwal - Mathematics

Factorize:

a2 + a – 3a2 - 3

RS Aggarwal & V Aggarwal - Mathematics

Factorize:

2a(x + y) -3b(x + y)

RS Aggarwal & V Aggarwal - Mathematics

Factorize:

8 – 4a – 2a3 + a4

RS Aggarwal & V Aggarwal - Mathematics

Factorize:

a2 + ab(b + 1) + b3

RS Aggarwal & V Aggarwal - Mathematics