Q. 224.1( 7 Votes )
If x + 1 is a factor of ππ₯3 + π₯2β2π₯ + 4πβ9, find the value of a.
Answer :
let p(x) = ax3 + x2 β 2x + 4a β 9 and g(x) = x + 1
Putting g(x) = 0 βΉ x + 1= 0 βΉ x = β 1
According to the factor theorem if g(x) is a factor of p(x) then p ( β 1) = 0
p( β 1) = a( β 1)3 + ( β 1)2 β 2( β 1) + 4a β 9 = 0
βΉ3a β 6 = 0 βΉ a = 2
Rate this question :






















Factorize:
x3 – 2x2y + 3xy2 – 6y3
RS Aggarwal & V Aggarwal - MathematicsFind the value of a for which the polynomial is divisible by (x+3).
Factorize:
a2 + a – 3a2 - 3
RS Aggarwal & V Aggarwal - MathematicsFactorize:
2a(x + y) -3b(x + y)
RS Aggarwal & V Aggarwal - MathematicsFactorize:
8 – 4a – 2a3 + a4
RS Aggarwal & V Aggarwal - MathematicsIf π + π + π = 9 and ππ + ππ + ππ = 26, find π2 + π2 + π2.
NCERT Mathematics ExemplarShow that p β 1 is a factor of p10 β 1 and also of p11 β 1.
NCERT Mathematics ExemplarFactorize:
a2 + ab(b + 1) + b3
RS Aggarwal & V Aggarwal - MathematicsFind the value of m so that 2x β 1 be a factor of 8π₯4 + 4π₯3β16π₯2 + 10π₯ + π.
NCERT Mathematics Exemplar