Q. 224.1( 7 Votes )

# If x + 1 is a factor of ππ₯^{3} + π₯^{2}β2π₯ + 4πβ9, find the value of a.

Answer :

let p(x) = ax^{3} + x^{2} β 2x + 4a β 9 and g(x) = x + 1

Putting g(x) = 0 βΉ x + 1= 0 βΉ x = β 1

According to the factor theorem if g(x) is a factor of p(x) then p ( β 1) = 0

p( β 1) = a( β 1)^{3} + ( β 1)^{2} β 2( β 1) + 4a β 9 = 0

βΉ3a β 6 = 0 βΉ a = 2

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