Q. 214.0( 8 Votes )

# Find the value of m so that 2x β 1 be a factor of 8π₯^{4} + 4π₯^{3}β16π₯^{2} + 10π₯ + π.

Answer :

let p(x) = 8x^{4} + 4x^{3}β16x^{2} + 10x + m and g(x) = 2x β 1

Putting g(x) = 0 βΉ 2x β 1 = 0 βΉ x = 1/2

According to the factor theorem if g(x) is a factor of p(x) then p (1/2) = 0

p(1/2) = 8(1/2)^{4} + 4(1/2)^{3}β16(1/2)^{2} + 10(1/2) + π = 0

βΉ

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