Q. 25.0( 1 Vote )

Find f-1</su

Answer :

(i) A = {0, –1, –3, 2}; B = {–9, –3, 0, 6} & f(x) = 3x


We have f : A B and f(x) = 3x.


f = {(0, 3×0), (–1, 3×(-1)), (–3, 3×(-3)), (2, 3×2)}


f = {(0, 0), (–1, –3), (–3, –9), (2, 6)}


Recall that a function is invertible only when it is both one-one and onto.


Here, observe that distinct elements of the domain {0, –1, –3, 2} are mapped to distinct elements of the co-domain {0, –3, –9, 6}.


Hence, f is one-one.


Also, each element of the range {–9, –3, 0, 6} is the image of some element of {0, –1, –3, 2}.


Hence, f is also onto.


Thus, the function f has an inverse.


We have f-1 = {(0, 0), (–3, –1), (–9, –3), (6, 2)}


(ii) A = {1, 3, 5, 7, 9}; B = {0, 1, 9, 25, 49, 81} & f(x) = x2


We have f : A B and f(x) = x2.


f = {(1, 12), (3, 32), (5, 52), (7, 72), (9, 92)}


f = {(1, 1), (3, 9), (5, 25), (7, 49), (9, 81)}


Recall that a function is invertible only when it is both one-one and onto.


Here, observe that distinct elements of the domain {1, 3, 5, 7, 9} are mapped to distinct elements of the co-domain {1, 9, 25, 49, 81}.


Hence, f is one-one.


However, the element 0 of the range {0, 1, 9, 25, 49, 81} is not the image of any element of {1, 3, 5, 7, 9}.


Hence, f is not onto.


Thus, the function f does not have an inverse.


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