Q. 19

# For what value of

let p(x) = x 3 β 2mx2 + 16, and g(x) = x + 2

Putting g(x) = 0 βΉ x + 2 = 0 βΉ x = β 2

According to factor theorem if p(x) is divisible by g(x), the remainder p(β2) should be zero.

p( β 2) = 0 βΉ ( β 2)3 β 2m( β 2)2 + 16 =0 β 8 β 8m + 16 = 0

βΉ 8m = 8 βΉ m = 1

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