# Show that p β 1 i

let h (p) = π 10 β 1,and g(p) = π β 1

Putting g (p) = 0 βΉ π β 1 = 0 βΉ π = 1

According to factor theorem if g(p) is a factor of h(p) , then h(1) should be zero

h(1) = (1)10 β 1 = 1 β 1 = 0

βΉ g (p) is a factor of h(p).

Now, we have h (p) = π 11 β 1, g (p) = π β 1

Putting g (p) = 0 βΉ π β 1 = 0 βΉ π = 1

According to factor theorem if g (p) is a factor of h (p) ,

Then h(1) = 0

βΉ (1)11 β 1 = 0 hence g (p) the factor of h (p)

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