Answer :
(i) Let p(x) =3π₯2 + 6π₯β24 and g(x) = x β 2
Zero of g(x) = 2
Here p(2) = 3(2)2 + 6 (2) β 24 = 12 + 12 β 24 = 0
So g(x) is a factor of p(x)
(ii) Let p(x) = 4π₯2 + π₯β2 and g(x) = x β 2
Zero of g(x) = 2
P(2) = 4(2)2 + 2β2 = 16 β 0
Hence g(x) is not a factor of p(x)
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