Q. 155.0( 1 Vote )

# The sum of first n terms of a certain series is given as 3n2– 2n. Show that the series is an arithmetic series.

For n = 1,

Sum = 3(1)2–2(1) = 1

Therefore, first term = 1

For n = 2,

Sum = 3(2)2 – 2(2) = 12 – 4 = 8

Second term = 8–1 = 7

For n = 3,

Sum = 3(3)2 – 2(3) = 21

Third term = 21– 8 = 13

Series : 1, 7, 13…..

This is an arithmetic progression as the difference between two terms is constant.

Common difference = 7–1 = 13–7 = 6

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Interactive Quiz:Euclid's Division Lemma44 mins
Fundamental Theorem of Arithmetic-238 mins
Champ Quiz | Fundamental Principle Of Arithmetic41 mins
Fundamental Theorem of Arithmetic- 143 mins
Euclids Division Lemma49 mins
Quiz | Imp Qs on Real Numbers37 mins
NCERT | Imp. Qs. on Rational and Irrational Numbers44 mins
Application of Euclids Division Lemma50 mins
Relation Between LCM , HCF and Numbers46 mins
Quiz | Fun with Fundamental Theorem of Arithmetic51 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses