Q. 115.0( 7 Votes )

Solve: 1 + 6 + 11 + 16 + ….. + x = 148.

Answer :

In the A.P.


First term = 1


Common difference = 6 – 1 = 5


Sum of terms =


148 =


148 =


296 = n (5n–3)


5n2 – 3n –296 = 0


5n2 –40n + 37n –296 = 0


5n(n–8) + 37(n–8) = 0


(n–8)(5n + 37) = 0


n = 8 or 5n = –37


As negative value of n is not possible, n = 8


x = 8th term of the series


x = 1 + (8–1)5


x = 1 + 35 = 36


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