Q. 95.0( 1 Vote )

# If the product of three consecutive terms in G.P. is 216 and sum of their products in pairs is 156, find them.

Let the first term of G.P be .

second term = a and third term = ar.

(where, r is the common ratio)

sum of three terms is 156 a3 = 216

a = 6. ……..(1)

Also,sum of their product in pairs is 216.  ………(2)

Substituting (1) in (2), we get- 36(1 + r + r2) = 156r

36 + 36r + 36r2 = 156r

36 -120r + 36r2 = 0

12(3r2-10r + 3) = 0

3r2-10r + 3 = 0

3r2-9r-1r + 3 = 0

3r(r-3) -1(r-3) = 0

(3r-1)(r-3) = 0 Now, G.P will be-   18, 6, 2 or 2, 6, 18 are the three consecutive terms.

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