Answer :

Given: p(x) = x^{3} – 6x^{2} + 14x – 3 and g(x) = 1 – 2x

As we know by Remainder Theorem,

If a polynomial p(x) is divided by a linear polynomial (x – a) then, the remainder is p(a)

Therefore, remainder when p(x) is divided by g(x) is

∴ the remainder when x^{3} – 6x^{2} + 14x – 3 is divided by 1 – 2x is

Result Verification:

We can see that the remainder is .

Hence, verified.

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