p(x) = ax2 + bx + c; a ≠ 0, a, b, c ε R.

Substituting a = 6, b = 17 and c = 11, we get the required quadratic polynomial

p(x) = 6x2 + 17x + 11.

(2) The cubic polynomial is,

p(x) = ax3 + bx2 + cx + d; a ≠ 0, a, b, c, d ε R.

Substituting a = 1, b = —1, c = —1 and d = 1, we get the required cubic polynomial

p(x) = x3 – x2 – x + 1.

p(x) = ax + bx + c; a ≠ 0, a, b, c ε R.

Substituting a = 5, b = 7 and c = 2, we get the required quadratic polynomial

p(x) = 5x2 + 7x + 2.

(4) The cubic polynomial is,

p(x) = ax + bx + cx + d; a ≠ 0, a, b, c, d ε R.

Substituting a = 1, b = –3, c = –1 and d = 3, we get the required cubic polynomial

p(x) = x3 – 3x2 – x + 3.

(5) The cubic polynomial is,

p(x) = ax3 + bx2 + cx + d; a ≠ 0, a, b, c, d ε R.

Substituting a = 3, b = –5, c = –11 and d = –3, we get the required cubic polynomial

p(x) = 3x3 – 5x2 – 11x – 3.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

Find the zeros ofGujarat Board Mathematics

3 is a zero of p(Gujarat Board Mathematics