Q. 34.0( 318 Votes )
Obtain all other zeroes of 3x4 + 6x3 - 2x2 - 10x - 5, if two of its zeroes areand
p(x) = 3x4 + 6x3 - 2x2 - 10x - 5
Since the two zeroes are .
is a factor of 3x4 + 6x3 - 2x2 - 10x - 5.
Therefore, we divide the given polynomial by .
Dividend = (Divisor × quotient) + remainder
3 x4 + 6 x3 - 2x2 - 10 x - 5 =
3 x4 + 6 x3 - 2 x2 - 10 x - 5 =
As (a+b)2 = a2 + b2 + 2ab
3 x4 + 6 x3 - 2 x2 - 10 x - 5 = 3 () (x + 1)2
Therefore, its zero is given by x + 1 = 0.
⇒ x = −1,-1
Hence, the zeroes of the given polynomial are and - 1 , -1.
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