Answer :
Here p(x) = x2 — 81
To find the zeros of p(x), let p(x) = 0
∴ x2 – 81 = 0
∴ (x)2 – (9)2 = 0
∴ (x – 9) (x + 9) = 0
[Using the identity: (a2 – b2) = (a – b) (a + b)]
∴ x = 9 or x = –9
–9 and 9 are the zeros of the quadratic polynomial p(x).
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