Answer :

f(x) = x + 1 and g(x) = ex


Range of f = R Domain of g= R gof exist


Range of g = (0, ) = Domain of f = R fog exist


Now,


gof(x) = g(f(x)) = g(x + 1) = ex + 1


And


fog (x) = f(g(x))= f(ex) = ex + 1


Hence, fog(x) = ex + 1 and gof(x) = ex + 1


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