Q. 105.0( 1 Vote )

Find the length of the chord of a circle of radius 5cm subtending an angle of 108° at the centre.

Answer :


Let AB be the chord of a circle of radius 5 cm with O as centre.


Draw OC perpendicular to AB.


C is the midpoint of AB and AOB = 108°


Then AOC = = 54°


In right angled triangle OCA,


sin 54° =


sin 54° =


AC = sin 54° × 5


= 0.8090 × 5


= 4.045 cm


Length of the chord AB = AC × 2 = 4.045 × 2 = 8.90 cm


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Foundation | Trigonometic RatioFoundation | Trigonometic RatioFoundation | Trigonometic Ratio38 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses