Answer :


second term = a and third term = ar.


(where, r is the common ratio)


sum of three terms is 7



……..(1)





………(2)


Now, R.H.S of equation (1) & (2) is equal-


L.H.S of equation (1) = L.H.S of equation (2)



a2 = 4


a = √4


a = 2


Now substituting a = 1 in (2), we get-



2 + 2r + 2r2 = 7r


2r2-5r + 2 = 0


2r2-4r-r + 2 = 0


(2r-1)(r-2) = 0



Now, G.P will be-





4, 2, 1 or 1, 2, 4 are the three consecutive terms.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Merchant of Venice (Summary and Important Questions)Merchant of Venice (Summary and Important Questions)Merchant of Venice (Summary and Important Questions)30 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

The fifth term ofTamil Nadu Board - Math

Find out which ofTamil Nadu Board - Math

Which term of theTamil Nadu Board - Math

If aTamil Nadu Board - Math

A company purchasTamil Nadu Board - Math

If ₹1000 is deposTamil Nadu Board - Math

If the third termTamil Nadu Board - Math

The common ratio Tamil Nadu Board - Math

If xTamil Nadu Board - Math

If the product ofTamil Nadu Board - Math