Answer :
Let the breadth (b) of the rectangular field be x meters.
∴ Twice of the breadth = 2x meters.
The length of the field is 8 meters less than twice the breadth.
∴ The length of the field = l = (2x – 8) meters.
The perimeter of the rectangular field = 56 meters.
Perimeter of rectangle = 2 (l + b)
According to the given condition,
2 (2x – 8 + x) = 56
⇒ 2 (3x – 8) = 56
6x – 16 = 56
⇒ 6x = 56 + 16 (Transposing 16 to RHS)
6x = 72
⇒ x = 
(Transposing 6 to RHS)
x = 12
The breadth of the field = x = 12 meters.
The length of the field = 2x – 8 = 2 (12) – 8 = 24 – 8
= 16 meters.
∴ The length and breadth of the rectangular field is 16 meters and 12 meters respectively.
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