Answer :
Let the weight of the first piece of pizza be x g.
The first piece is 7g lighter than the second piece.
∴ The weight of the second piece of pizza = (x + 7) g.
The first piece is 4g heavier than the third piece.
∴ The weight of the third piece of pizza = (x – 4) g.
The total weight of the pizza = 300g.
According to the given condition,
x + (x + 7) + (x – 4) = 300
⇒ x + x + 7 + x – 4 = 300
3x + 3 = 300
⇒ 3x = 300 – 3 (Transposing 3 to RHS)
3x = 297
⇒ x = 
(Transposing 3 to RHS)
x = 99
The weight of the first piece = x = 99g.
The weight of the second piece = x + 7 = 99 + 7 = 106g.
The weight of the third piece = x – 4 = 99 – 4 = 95g.
∴ The weights of the three pieces of pizza are 95g, 99g and 106g.
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