Q. 75.0( 3 Votes )

Let f: R →<

Answer :

We have, f: R R and g: R R are two functions defined by


f (x)= x2 and g(x) = x + 1


Now,


fog (x) = f(g(x)) = f(x + 1) =(x + 1)2


fog(x) = x2 + 2x + 1 ……(i)


gof(x) = g(f(x)) = g(x2) = x2 + 1 ……(ii)


from (i) & (ii)


fog ≠ gof


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