Answer :

0 and 1 are the zeroes of the polynomial f(x) = 2x3-3x2+ ax + b


f(0) = 0 and f(1) = 1


Now,


f(x) = 2x3-3x2+ ax + b


f(0) = 2(0)3 – 3(0)2+ a(0) + 0


2 × 0– 3 × 0 + a × 0 + b = 0


0– 0 + 0 + b = 0


b = 0


And,


f(1) = 2(1)3 – 3(1)2+ a(1) +1


2 × 1– 3 × 1 + a × 1 + b = 0


2– 3 + a + b = 0


2– 3 + a + 0 = 0 [ b = 0]


-1 + a = 0


a = 1


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