Q. 4

# Find the 12

Given A.P. √2, 3√2, 5√2 …

Here, first term, a = √2

We know that common difference, d = a1 – a.

d = 3√2 - √2 = 2√2

We know that nth term of A.P. , tn = a + (n – 1) d.

t12 = √2 + (12 – 1) (2√2)

= √2 + 11 (2√2)

= √2 + 22 √2

= 23√2

12th term of A.P. i.e. t12 = 23√2

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

If a clock strikeTamil Nadu Board - Math

If 9th termTamil Nadu Board - Math

The sum of Tamil Nadu Board - Math

If <Tamil Nadu Board - Math

If <Tamil Nadu Board - Math

Find the thTamil Nadu Board - Math

If ax<Tamil Nadu Board - Math

A man has sTamil Nadu Board - Math

How many teTamil Nadu Board - Math

Find the 17Tamil Nadu Board - Math