The perimeter of

Let the length be “l” and breadth be “b”

Given:
Perimeter of rectangle = 154 m
Length is two more than twice of breadth, 
twice of breadth means  2b, and 2 more than this means : 2b + 2
Therefore,
l = (2b + 2) m          
Then, perimeter = 2(l + b) = 154 m
Putting the value of l in above equation,     

2{(2b + 2) + b} = 154

2{2b + b + 2} = 154
2{3b + 2} = 154
6b + 4 = 154
6b = 154 - 4
6b = 150

Hence, Breadth of the rectangle = 25 m
So, length of the rectangle = 2b + 2 = 2(25) + 2 = 52 m