Answer :
Since, f:R → R and g:R → R
fog:R → R and gof:R → R
f (x) = x and g (x) = |x|
Now, gof(x)=g(f(x) =g(x)
⇒ gof(x) =|x|
and, fog(x) = f(g(x)) = f (|x|)
⇒ fog(x)=|x|
Hence, gof(x) = fog(x) = |x|
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