1 A 1 B 1 C 1 D 1 E 1 F 2 3 4 5 6 7 8 9 10 11 12 13 14

RD Sharma - Volume 1

Exercise 2.1

1 A 1 B 1 C 2 A 2 B 2 C 3 4 5 A 5 B 5 C 5 D 5 E 5 F 5 G 5 H 5 I 5 J 5 K 5 L 5 M 5 N 5 O 5 P 5 Q 6 7 8 A 8 B 8 C 9 A 9 B 10 11 12 13 14 15 16 17 18 19 20 21 A 21 B 21 C 22 23

Exercise 2.2

1 A 1 B 1 C 1 D 1 E 1 F 2 3 4 5 6 7 8 9 10 11 12 13 14

Exercise 2.3

1 A 1 B 1 C 1 D 1 E 1 F 1 G 1 H 1 I 2 3 4 5 6 7 8 9 10 11 A 11 B 11 C 11 D 12 13

Exercise 2.4

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24

Very short answer

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MCQ

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Q. 1 A

Find gof and fog

Class 12th RD Sharma - Volume 1 2. Functions

Answer :

Since, f:R → R and g:R → R

fog:R → R and gof:R → R

Now, f(x) = 2x + 3 and g(x) = x² + 5

gof(x) = g(2x + 3) = (2x + 3)² + 5

⇒ gof(x) = 4x² + 12x + 9 + 5 = 4x² + 12x + 14

fog (x) = f(g(x)) = f (x² + 5) = 2 (x² + 5) + 3

⇒ fog(x)= 2x² + 10 + 3 = 2x² + 13

Hence, gof(x) = 4x² + 12x + 14 and fog (x) = 2x² + 13

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