# Two complementary angles differ by 12o, find the angles?

Let one of the angles be x°.

The two angles differ by 12°.

The second angle = (x + 12)°.

The two angle are complementary angles.

The sum of two complementary angles is 90°.

According to the given condition,

x + x + 12 = 90

2x + 12 = 90

2x = 90 – 12 (Transposing 12 to RHS)

2x = 78

x = (Transposing 2 to RHS)

x = 39

The first angle = x = 39°.

The second angle = x + 12 = 39 + 12 = 51°.

The two complementary angles are 39° and 51°.

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