Answer :

Let Baichung’s father age is x.

Given,

Baichung's father is 26 years younger than Baichung's grandfather

⇒ Age of Baichung's father = x + 26

and

Baichung's father is 29 years older than Baichung

⇒ Age of Baichiung = x - 29

Now,

Sum of ages = 135

⇒ x + (x+ 26) + (x- 29) = 135

⇒ 3x -3 = 135

⇒ 3x = 138

⇒ x = = 46

So, Baichung's Father Age = 46 years

Baichung's Age = x - 29 = 46 - 29 = 17 years

Baichung's grandfather Age = x + 26 = 46 + 26 = 72 years

Rate this question :

<span lang="EN-GBNCERT - Mathematics Exemplar

<span lang="EN-GBNCERT - Mathematics Exemplar

<span lang="EN-GBNCERT - Mathematics Exemplar

<span lang="EN-GBNCERT - Mathematics Exemplar

<span lang="EN-GBNCERT - Mathematics Exemplar

<span lang=NCERT - Mathematics Exemplar

The base of an isRS Aggarwal - Mathematics

<span lang=NCERT - Mathematics Exemplar

If numeratoNCERT - Mathematics Exemplar