# <span lang="EN-US

Let the triangle be Δ ABC.

The triangle has two equal sides, i.e. AB = BC.

Let the length of the third side, ℓ (AC), be x meters. ℓ (AB) = ℓ (BC) = (2x – 5) meters.

The perimeter of Δ ABC = 55 meters.

According to the given condition,

ℓ (AB) + ℓ (BC) + ℓ (AC) = 55

2x – 5 + 2x – 5 + x = 55

5x – 10 = 55

5x = 55 + 10 (Transposing 10 to RHS)

5x = 65

x = (Transposing 5 to RHS)

x = 13

The lengths of the sides of the triangle are

ℓ (AB) = 2x – 5 = 2 (13) – 5 = 26 – 5 = 21 meters.

ℓ (BC) = 2x – 5 = 2 (13) – 5 = 26 – 5 = 21 meters.

ℓ (AC) = x = 13 meters.

The lengths of the sides of Δ ABC are 21 meters, 21 meters and 13 meters.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

<span lang="EN-USAP - Mathematics

<span lang="EN-USAP - Mathematics

<span lang="EN-USAP - Mathematics

<span lang="EN-USAP - Mathematics

<span lang="EN-USAP - Mathematics

<span lang="EN-USAP - Mathematics

<span lang="EN-USAP - Mathematics

<span lang="EN-USAP - Mathematics

<span lang="EN-USAP - Mathematics

<span lang="EN-USAP - Mathematics