1 A 1 B 1 C 1 D 1 E 1 F 2 3 4 5 6 7 8 9 10 11 12 13 14

RD Sharma - Volume 1

Exercise 2.1

1 A 1 B 1 C 2 A 2 B 2 C 3 4 5 A 5 B 5 C 5 D 5 E 5 F 5 G 5 H 5 I 5 J 5 K 5 L 5 M 5 N 5 O 5 P 5 Q 6 7 8 A 8 B 8 C 9 A 9 B 10 11 12 13 14 15 16 17 18 19 20 21 A 21 B 21 C 22 23

Exercise 2.2

1 A 1 B 1 C 1 D 1 E 1 F 2 3 4 5 6 7 8 9 10 11 12 13 14

Exercise 2.3

1 A 1 B 1 C 1 D 1 E 1 F 1 G 1 H 1 I 2 3 4 5 6 7 8 9 10 11 A 11 B 11 C 11 D 12 13

Exercise 2.4

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24

Very short answer

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MCQ

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Q. 10

Consider f: N <sp

Class 12th RD Sharma - Volume 1 2. Functions

Answer :

We have,

ho(gof)(x)=h(gof(x))=h(g(f(x)))

= h(g(2x)) = h(3(2x) + 4)

= h(6x + 4) = sin(6x + 4) ∀x ∈N

((hog)of)(x) = (hog)(f(x))= (hog)(2x)

=h(g(2x))=h(3(2x) + 4)

=h(6x + 4) = sin(6x + 4) ∀x ∈N

This shows, ho(gof) = (hog)of

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