= h(g(2x)) = h(3(2x) + 4)
= h(6x + 4) = sin(6x + 4) ∀x ∈N
((hog)of)(x) = (hog)(f(x))= (hog)(2x)
=h(g(2x))=h(3(2x) + 4)
=h(6x + 4) = sin(6x + 4) ∀x ∈N
This shows, ho(gof) = (hog)of
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