Q. 73.7( 39 Votes )

The zeroes of the

Answer :

let p(x) = x2 + 99x + 127

x


=


=


=


= - 2.6/2, - 195.4/2


x = - 1.3, - 97.7


Both the zeroes are negative


OR


We know, in quadratic polynomial if the coefficients of the terms are of the same sign, then the zeroes of the polynomial are negative.


i.e. if either a > 0, b > 0 and c > 0 or a < 0, b < 0 and c < 0, then both zeroes are negative


So here, a = 1 > 0, b = 99 > 0 and c = 127 > 0


The zeroes are negative.

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