Answer :

From the integers given in the question 210 and 55, it is observed that 210 > 55. So by Euclid’s Division Lemma we get the following:

210 = 55 × 3 + 45


Her the remainder is 45 which is not equal to zero. So applying Euclid’s Division Lemma on divisor 55 and remainder 45.


55 = 45 × 1 + 10


Here the remainder is 10 which is not equal to zero. So applying Euclid’s Division Lemma on divisor 45 and remainder 10.


45 = 10 × 4 + 5


Here the remainder is 5 which is not equal to zero. So applying Euclid’s Division Lemma on divisor 10 and remainder 5.


10 = 5 × 2 + 0


So from the above relation is seen that remainder zero is obtained.


So the HCF of 210 and 55 is 5.


The entire process can be expressed in the following way:



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