Answer :

In a right angled ΔABC, AB = 25 cm, BC = 24 cm and AC = 7 cm.

__We know that in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.__

⇒ In ΔABC, AB^{2} = BC^{2} + AC^{2}

⇒ 25^{2} = 24^{2} + 7^{2}

⇒ 625 = 576 + 49

⇒ 625 = 625

∴ The given sides can be the sides of a right angled triangle.

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