# Write the first three terms of the following sequences whose nth terms are given by(i) (ii) cn = (–1)n3n+2 (iii) (i) Here, an = For n = 1, a1 = = = For n = 2, a2 = = = = 0

For n = 3, a3 = = = = 1

Hence, the first three terms of the sequence are , 0 and 1.

(ii) Here, cn = (-1)n 3n + 2

For n = 1, c1 = (-1)1 31 + 2 = (-1) 33 = (-1) (27) = -27

For n = 2, c2 = (-1)2 32 + 2 = (1) 34 = (1) (81) = 81

For n = 3, c3 = (-1)3 33 + 2 = (-1) 35 = (-1) (243) = -243

Hence, the first three terms of the sequence are -27, 81 and -243.

(iii) Here, zn = For n = 1, z1 = = = For n = 2, z2 = = = = 2

For n = 3, z3 = = = Hence, the first three terms of the sequence are , 2 and .

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