Q. 65.0( 1 Vote )

# If <span lang="EN

Let p(x) = x11 + 101 and g(x) = x + 1

By using remainder theorem put value of x + 1 = 0

x + 1 = 0

x = –1

Hence, p(– 1) will give the remainder of x11 + 101 divided by x + 1

P(– 1) = x11 + 101

P(– 1) = (–1)11 + 101

P(– 1) = 101 – 1

P(– 1) = 100

remainder is 100

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