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Let p(x) = ax2 + 2x + b

As (x + 2) and (2x + 1) are factors of p(x) hence each will divide p(x) leaving remainder as 0

Let us use the remainder theorem which states that if (x – a) divides a quadratic polynomial p(x) then p(a) = 0

First a = –2

p(a) = a(–2)2 + 2(–2) + b

0 = 4a – 4 + b

b = 4 – 4a …(i)

Now a = –1/2

p(a) = a(–1/2)2 + 2(–1/2) + b Multiply whole equation by 4

0 = a – 4 + 4b

4b = 4 – a …(ii)

Subtract (i) from (ii)

4b – b = (4 – a) – (4 – 4a)

3b = 4 – a – 4 + 4a

3b = 3a

a = b

a – b = 0

Hence proved

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