Answer :

If 4^{n} is divisible by 10 then it can end with digit zero

If it is divisible by 10 it has to be divisible by 5 and 2 both

The prime factorization of 14 is 2 × 2 which is 2^{2}

⇒ 4^{n} = (2^{2})^{n} = 2^{2n}

Observe that 2^{2n} is divisible by 2 (because and 2^{2n–1} is intan eger for n≥1) but not by 5 because there is no 5 in prithe me factorization of 4

Hence 4^{n} is not divisible by 10

Hence 4^{n ee}doesnot end with 0 for any natural number n

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