Answer :
Given: P = {x: x < 3, x ∈N}, Q = {x : x ≤ 2, x ∈W} where W is the set of whole numbers
To find: (P∪Q) × (P∩Q)
Explanation: Given P = {x: x < 3, x ∈N}
This means set P contains all natural numbers which are less than 3, so
P = {1, 2}
And Q = {x : x ≤ 2, x ∈W}
This means set Q contains all whole numbers which are less than or equal to 2, so
Q = {0, 1, 2}
Now
(P∪Q) is union of set P = {1, 2} and set Q = {0, 1, 2} elements, so
(P∪Q) = {0, 1, 2}
And,
(P∩Q) is intersection of set P = {1, 2} and set Q = {0, 1, 2} elements, so
(P∩Q) = {1, 2}
We need to find the Cartesian product of (P∪Q) = {0, 1, 2} and (P∩Q) = {1, 2}
So,
(P∪Q) × (P∩Q) = {(0, 1), (0, 2), (1, 1), (1, 2), (2, 1), (2, 2)}
This is the required Cartesian product.
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