Q. 165.0( 1 Vote )

If 2 and 3 are zeroes of polynomial 3x2 – 2kx + 2m. Find the value of k and m.

As 2 and 3 are zeroes of equation 3x2 – 2kx + 2m we will get 0 when we substitute x by 2 and 3

Let us substitute x = 2

3(2)2 – 2k(2) + 2m = 0

12 – 4k + 2m = 0

Divide whole equation by 2

6 – 2k + m = 0

m = 2k – 6 …(i)

Now substitute x = 3

3(3)2 – 2k(3) + 2m = 0

27 – 6k + 2m = 0

Substitute value of m from equation (i)

27 – 6k + 2(2k – 6) = 0

27 – 6k + 4k – 12 = 0

15 – 2k = 0

2k = 15

Put value of k in (i)

m = 15 – 6

m = 9

Hence and m = 9

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Champ Quiz |Revealing the relation Between Zero and Coefficients38 mins
Relation Between zeroes and Coefficients46 mins
Interactive Quiz - Geometrical Meaning of the Zeroes32 mins
Relationship between Zeroes and Coefficients-238 mins
Relationship between Zeroes and Coefficients-152 mins
Quiz - Division Algorithm38 mins
Interactive Quiz:Polynomials43 mins
Division Algorithm-130 mins
Relation b/w The Zeroes and Coefficients of Cubic Polynomials54 mins
Solving Imp. Qs. of Olympiad on Polynomials47 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses