# A cylindrical ves

Given internal diameter of cylinder = D = 10 cm

Internal radius of cylinder = R = D/2 = 10/2

Internal radius of cylinder = R = 5 cm

Height of cylinder = H = 10.5 cm

Diameter of solid cone = d = 7 cm

Radius of solid cone = r = d/2 = 7/2

Radius of solid cone = r = 3.5 cm

Height of cone = h = 6 cm

(i)Volume displaced out of cylinder

By Archimedes principle we can easily say that,

Volume displaced out of cylinder = Volume of the solid cone

V = 22 × 1.75 × 2

V = 77 cm3

The volume displaced out of cylinder is 77 cm3.

(ii)Volume left in cylinder

Volume left in cylinder = Volume of cylinder – Volume displaced out

Volume of cylinder = π(R)2H

Volume of cylinder = π × (5)2 × 10.5 (putting the given values)

Volume of cylinder = π × 25 × 10.5

Volume of cylinder = π × 262.5

Volume of cylinder = 22 × 37.5

Volume of cylinder = 825 cm3eqn1

Volume left in cylinder = 825 – 77 (from eqn1 and (i))

Volume left in cylinder = 748 cm3

The volume left in the cylinder is 748 cm3.

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