Q. 315.0( 3 Votes )

# A hollow sp

Answer :

External diameter of hollow sphere = D = 8 cm

⇒ External radius of hollow sphere = R = D/2

⇒ R = 8/2

⇒ R = 4 cm

Internal diameter of hollow sphere = d = 4 cm

⇒ Internal radius of hollow sphere = r = d/2

⇒ r = 4/2

⇒ r = 2 cm

Let the height of the resulting cone be ‘h’ cm

Let the volume of External sphere be V_{1} and that of internal be V_{2}.

__Explanation: Here the volume of hollow sphere will be equal to the volume of the resulting cone as the resulting cone is formed by melting the sphere.__

Volume of the External sphere=(put the value of R)

Volume of sphere = V = External volume – Internal volume

Given base radius of the resulting cone = r’ = 8 cm

Le the height be ‘h’ and volume of the resulting cone be V’

(putting value of r' )

Equate equation 3 and 4,

⇒ V = V’

⇒ 224 = 64h

⇒ h = 224/64

∴ h = 3.5 cm

__The height of resulting cone is 3.5 cm.__

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