Q. 255.0( 3 Votes )

Answer :

Given volume of each cube = 125 cm^{3}

Let the edge of each cube be ‘a’ cm

So, Volume of cube = a^{3}

⇒ a^{3} = 125

⇒ a = ∛(125)

∴ a = 5 cm →eqn1

Now when we join the two cubes then resulting cuboid will be of length twice that of the cube and breadth and height of the resulting cuboid will be same as that of the cube

⇒ length of cuboid = L = 2 × a

⇒ L = 2 × 5 (putting value of a from eqn1)

∴ L = 10 cm

Now, Breadth of cuboid = B = a

⇒ B = 5 cm

Similarly, height of the cuboid = H = 5 cm

__Note: Where ever in a question Surface Area is mentioned, it means Total surface area.__

Surface area = Total surface area = 2(LB + BH + HL)

⇒ S.A = 2((10 × 5) + (5 × 5) + (10 × 5))

⇒ S.A = 2(50 + 25 + 50)

⇒ S.A = 2 × 125

∴ S.A = 250 cm^{2}

__Surface Area of resulting cuboid is 250 cm ^{2}.__

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