Q. 44.0( 12 Votes )

Answer :

Given: height of frustum container = h = 24 cm

Radius of lower circular end = r = 8 cm

Radius of upper circular end = R = 20 cm

Cost of 1 litre milk = 24 Rs

Volume of milk completely fill the container = volume of frustum of cone

= 8 × 3.14 × (400 + 64 + 160) cm^{3}

= 8 × 3.14 × 624 cm^{3}

= 15674.88 cm^{3}

Now, 1 litre is 1000 cm^{3}

∴ 15674.88 cm^{3} = 15674.88/1000 = 15.67488 litres

∴ Cost of milk which can completely fill the container = 15.67488 × cost of 1 litre milk

= 15.67488 × 24 Rs

= 376.19712 Rs

∴ Cost of milk which can completely fill the container = 376.19712 Rs

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PREVIOUSA metallic bucket, open at the top, of height 24 cm is in the form of the frustum of a cone, the radii of whose lower and upper circular ends are 7 cm and 14 cm respectively. Find(i) the volume of water which can completely fill the bucket;(ii) the area of the metal sheet used to make the bucket.NEXTA container, open at the top and made up of metal sheet, is in the form of a frustum of a cone of height 16 cm with diameters of its lower and upper ends as 16 cm and 14 cm respectively. Find the cost of metal sheet used to make the container, if it costs Rs 10 per 100 cm2.