Q. 214.0( 11 Votes )

# An oil funnel mad

Answer :

Divide the funnel into two parts frustum and cylinder as shown in the figure

Parameters of frustum:

Diameter of upper circular end = 18 cm

∴ Radius of upper circular end = r = 18/2 = 9 cm

The radius of cylinder is equal to the radius of lower circular end of frustum

∴ radius of lower circular end = R = 4 cm

Height of frustum = total height – height of cylinder

= 22 – 10

= 12 cm

∴ height of frustum = h = 12 cm

Total surface area of frustum = πr^{2} + πR^{2} + π(R + r)l cm^{2}

Where l = slant height

∴ l = 13 cm

Since for the frustum part of the funnel we don’t require the upper circular end and the lower circular end hence we need to subtract those areas from total surface area.

Area of upper circular end = πr^{2}

Area of lower circular end = πR^{2}

total surface area = πr^{2} + πR^{2} + π(R + r)l- πr^{2}- πR^{2}

= π(R + r)l

= 3.14 × (9 + 4) × 13

= 530.66 cm^{2}

∴ total surface area of frustum for which tin is required = 530.66 cm^{2}

Parameters of cylinder:

Height of cylinder = 10 cm

Radius of cylinder = 4 cm

∴ Area of tin require to make cylinder = 2π × (radius) × (height)

= 2 × 3.14 × 4 × 10

= 251.2 cm^{2}

∴ Area of tin required to make the funnel = area of frustum for which tin is required + area

of tin require to make cylinder

∴ area of tin required to make funnel = 530.66 + 251.2

= 781.86 cm^{2}

∴ Area of tin sheet require to make the funnel = 781.86 cm^{2}

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