Answer :


Here, p is the principal, r is the rate of interest per annum and t is the time in years.

Solving the differential equation we get,

As it is given that the principal doubles itself in 10 years, so

Let the initial interest be p1 (for t = 0 ), after 10 years p1 becomes 2p1.

Thus, for ( t = 0) …(i)


Substituting (i) in (ii), we get,

Rate of interest = 6.931

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