Answer :

Given:


Here, p is the principal, r is the rate of interest per annum and t is the time in years.


Solving the differential equation we get,






As it is given that the principal doubles itself in 10 years, so


Let the initial interest be p1 (for t = 0 ), after 10 years p1 becomes 2p1.


Thus, for ( t = 0) …(i)


…(ii)


Substituting (i) in (ii), we get,







Rate of interest = 6.931


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