Q. 555.0( 1 Vote )
A curve passes through the point (0, -2) and at any point (x, y) of the curve, the product of the slope of its tangent and y-coordinate of the point is equal to the x-coordinate of the point. Find the equation of the curve.
Answer :
Given that the product of slope of tangent and y coordinate equals the x-coordinate i.e., 
We have, 
⇒ 
⇒ 
For the curve passes through (0, -2), we get c = 2,
Thus, the required particular solution is:-
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PREVIOUSFind the equation of a curve which passes through the origin and whose differential equation is NEXTA curve passes through the point (-1, 1) and at any point (x, y) of the curve, the slope of the tangent is twice the slope of the line segment joining the point of contact to the point (-4, -3). Find the equation of the curve.
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