Q. 323.9( 23 Votes )

# In a corner of a rectangular field with dimensions 35 m × 22 m, a well with 14m inside diameters is dug 8 m deep. The earth dug out is spread evenly over the remaining part of the field. Find the rise in the level of the field.

Answer :

Given,

Diameter of the well = 14 m

Radius of the well = 7 m

Height of the well = 8 m

Now,

Volume of the earth dug out of the well = πr^{2}h

= × 7 × 7 × 8 = 1,232 m^{3}

Area on which earth dug out is spread = l × b - r^{2}h

= 35 × 22 - × 7 × 7

= 770 - 154 = 616 m

Level of the earth raised = = 2 m

So, the rise in the level of the field is 2 m.

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