Answer :

Given,

Width of the canal = 6 m

Depth of the canal, = 1.5 m

Length of the cuboid = 666.67 m

Water is flowing at a speed of 4 km/hr = 4000m/hr

Thus,

Area irrigated in 10 minutes = hour = x 4000 = 666.67 m

Hence,

Volume of the water flowing in hour = Volume of the canal

⇒ Volume of the water flowing in hour = 666.67 x 6 x 1.5 = 6000.03 = 60000 m^{3}

Let a m^{2} is the area irrigated in hour,

Then,

⇒ a × = 6000

⇒ a = m^{2} = 75000 m^{2}

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