Answer :
Given,
Width of the canal = 6 m
Depth of the canal, = 1.5 m
Length of the cuboid = 666.67 m
Water is flowing at a speed of 4 km/hr = 4000m/hr
Thus,
Area irrigated in 10 minutes = hour =
x 4000 = 666.67 m
Hence,
Volume of the water flowing in hour = Volume of the canal
⇒ Volume of the water flowing in hour = 666.67 x 6 x 1.5 = 6000.03 = 60000 m3
Let a m2 is the area irrigated in hour,
Then,
⇒ a × = 6000
⇒ a = m2 = 75000 m2
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